برندینگ و برندسازی: unix - Access all the provide parameters and print them in bash

۱۳۹۶ اسفند ۱۲, شنبه

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I have a custom command that I create call PUSH

I want to run

PUSH #1 #2 #3 #4

I want to dynamically access all my arguments, I seem to have a hard time.

How do I correctly do it?

I want to access

#1 #2 #3 #4

I know I can not use $1, $2, $3, or $4.

I've tried

PUSH a b c | echo $@

How would one go about and do this ?

I'm open to any suggestions at this moment.

Any hints/suggestions / helps on this be will be much appreciated!

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