Python Monty Hall simulation giving equal odds for both switching and not

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I created a (rather complicated) Monty Hall simulation in Python, but, when run, returns equal odds of 33% for both Switching and not, when I know that, in reality, this cannot be the case and is not the case. What is wrong?

import math
import random

Right = 0
def TestWithSwitch():
global Right
wdoor = math.floor(random.random() * 3)
doors = [0,0,0]
doors[wdoor] = 1
Ldoors = [0,0]
i=0
##Declare winning door to be the winning door in the door Array

for x in range(0, 3):
 if(x!=3):
 if(doors[x] != 1):
 Ldoors[i] = x
 i+=1
##Chose the losing doors to be the doors that aren't the winning door
choice = math.floor(random.random() * 3)
DoorOut = 0
##Pick a Choice
LChose = False
for y in range(0, 2):
 if(y!= 2):
 if(Ldoors[y] == choice):
 DoorOut = Ldoors[(y+1)%2]
 LChose = True
if(LChose == False):
 DoorOut = Ldoors[math.floor(random.random() * 2)]
Reserved = [DoorOut, choice]

##DoorOut is chosen from any of the losing doors we didn't pick as our choice, and is the door the computer is told doesn't have the prize
for z in range(0, 3):
 if(z!= 3):
 if(z in Reserved == False):
 choice = z
 ##Make our new choice the other choice that we didn't previously choose
 if(choice == wdoor):
 Right+=1

def TestNoSwitch():
 global Right
 wdoor = math.floor(random.random() * 3)
 doors = [0,0,0]
 doors[wdoor] = 1
 Ldoors = [0,0]
 i=0


 for x in range(0, 3):
 if(x!=3):
 if(doors[x] != 1):
 Ldoors[i] = x
 i+=1
 choice = math.floor(random.random() * 3)
 if(choice == wdoor):
 Right+=1



for j in range(1, 10000):
 ## TestWithSwitch() and TestNoSwitch() both result in about 1/3. You can 
test by putting either function in.
 if(j == 9999):
 print(Right/10000)

I know that switching should return 66% odds, while not should return 33% odds. THe odds I recieve tend to not even add up to 100% , but about two thirds, which is a probabilistic impossibility.

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